2(6x^2+3x-1)=0

Solution for 2(6x^2+3x-1)=0 equation:

2(6x^2+3x-1)=0

We multiply parentheses

12x^2+6x-2=0

a = 12; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·12·(-2)
Δ = 132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{132}=\sqrt{4*33}=\sqrt{4}*\sqrt{33}=2\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{33}}{2*12}=\frac{-6-2\sqrt{33}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{33}}{2*12}=\frac{-6+2\sqrt{33}}{24}
$